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Two things which might be of use are 1) adapters that convert the coax/barrel connector of the wall-wart into screw terminals - about 50 cents on eBay, and 2) a DC-to-DC module which generates user-settable regulated DC voltage - about $1 on eBay.  Both of these have been discussed in other OGR threads.

 

ogr dc wall wart lm2596

For example, many Lemax lighted accessories and Miller Engineering animated signs operate off 4.5V DC (3 x 1.5V batteries).  There have been many threads about using 12V DC LED strips for layout lighting (buildings, station platforms, etc.).

 

Most wall-warts are electrically isolated which make them suitable for isolated-rail block-occupancy detectors or layout accessory triggers.

 

Some motor-driven layout accessories work best if you can fine-tune the voltage rather than being "stuck" with the fixed accessory voltage from many transformers.  A recycled wall-wart plus a regulator module is an economical way to do so.

 

One size does not fit all so a specific wall-wart may not have a suitable voltage/current/power capability to power a specific application.  But these are minor details which can be discussed as needed. 

 

And to Arthur's point, definitely read the fine-print to see if the wall-wart may be AC output.  In which case you can also buy AC-in, DC-out adjustable regulator modules for not much more.

 

Bottom line: answer to your question is "yes".

 

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  • ogr dc wall wart lm2596
Last edited by stan2004

That's a really cool little product, the coax-to-screw terminal thingie. I didn't know they existed. I can definitely see a use for an array of them in my tool box, when trying to match power units to equipment.  There are about ten different permutations of inside- and outside diameters, though. Do they make them for all the combinations?  Also, the one in the photo is marked for + and -.  However, my experience is that there is no standard convention for polarity across the industry.  I would be careful (test with a voltmeter or a diode/lamp tester) before believing the polarity stamp.

 

For the work bench I can see having them handy. But I question their usefulness when connecting the W-W for after-market applications like our trains. Why not just cut the plug off, and terminate the wires on the accessory?

Last edited by Arthur P. Bloom

The ones I use from eBay are for the 5.5/2.1mm size which seems the most common for older surplus wall-warts.  I don't know what other versions are readily available. 

 

Yes, always prudent to confirm polarity of any DC device in addition to its voltage/current suitability.  One alternative is to simply an AC-in, DC-out module.  That is, the AC-in modules also accept DC-in of either polarity; so if one could only "stock" one type of regulator module, the AC-in, DC-out type would be the jack-of-all-trades way to go.  That is, it would directly connect to the AC accessory voltage from train transformers or to the AC or DC voltage (of either polarity) from a wall wart.

 

To each his own but I've found that these adapter give more flexibility.  If wires are soldered, it's a nuisance to disconnect the accessory - other than pulling the AC plug which can be inconvenient when crawling under a layout.  I've run into wall-warts that have braided/shielded wires which can be and difficult to work with depending on one's wire-working skills.

Nope, that's still not correct.  Look again, the three LED's are in series with a 150 ohm resistor.  Each three segment section only draws 20ma at 12 volts, three volts are dropped across each LED, and 3 volts are dropped across the resistor.

 

Here's a standard strip with 12VDC from a bench supply feeding it.  Note the ammeter reading.

 

 

 

LED Strip Test

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Sorry, John. Each 5050 carrier has 3 separate leds in it. There are 3 carriers per segment. you are correct that there are 3 leds in series with a 150 ohm resistor and each of the sets draws 20 ma. 3 sets of 3 in parallel draw 60 ma per segment. I'll have to look up the specifications-- here's a copy of one companies 5050 spec sheet--

Screen Shot 11-26-14 at 09.46 PM

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Last edited by Fec fan

Like I said, the most common LED strip is the one with 300 LED's.  Each LED draws 20ma, and three of them are in series with that 150 ohm resistor.  That group in total draws 20ma at 12V.  Multiply that .02 amps time 100 and you get 2 amps.

 

I realize that if you had nine LEDs in this configuration that the max power would be 60ma, that's .02 * 3, even I can handle that math.

 

FWIW, for passenger car lighting, I use a small fraction of that current for lighting these, more like around 2-3 ma for each 3-LED group.  I light the whole 18" passenger car on around 20-25ma total current for the car.  If you were to actually run them at the full rated current, it would look like sunrise inside the car, WAY too bright.

 

For my lighting modules, I vary the total current between about 5ma to 45ma with the intensity adjustment.  So far, two people have asked my how to lower the intensity below my minimum setting!  That indicates many people like their lighting even lower than I run mine.

 

 

Last edited by gunrunnerjohn

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