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Pictures below show my scratch-built truss bridge, shoes and piers. On my layout, the shoes rest on U-shaped "steel" pads which rest atop the abutments without being secured. The underside corners of the lower main truss beams have a thin (1/32") plate with a recess into which the tops of the shoes fit. The bridge is just placed onto the tops of the shoes. The "steel" pads can be moved as necessary so the bridge rests squarely atop the shoes. The weight of the track (and trains) is sufficient to prevent the bridge from moving. Shims of thin wood or paper can be placed beneath the shoes so that the bridge is supported equally on each corner. If the layout has to be transported, the bridge can be lifted off the layout just by removing the track - which is a single 40-inch rigid Atlas O straight.

MELGAR

MELGAR_5_TRUSS_BRIDGE_SHOE_EMELGAR_6_TRUSS_BRIDGE_SHOE_E

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FrankM,

I debated for a while before deciding to answer your question. Your modeling and scenery are so extraordinary, realistic and artistic as to make the mounting of the bridge irrelevant to anyone except a structural engineer. The full-sized bridge design is such that it would be supported only by bridge shoes and only at the four corners. The shoes allow for expansion and contraction due to changes in temperature and prevent certain types of forces (and moments) from being imposed on the bridge's structural members. The relevant point here, which definitely applies to me, is that "Imagination is more important than knowledge. Knowledge has limits." I hope you're getting along OK.

MELGAR

Last edited by MELGAR

MELGAR, THANK YOU for so informative a reply about bridge shoes. Your succinct explanation was a nice lesson to learn.

And more importantly, your very, very kind viewpoint of my layout work has given me the first big smile I have had in a couple weeks, now.

Thank you, also, for your thoughtfulness in asking about how I am getting along. Little by little, bit by bit. I am learning in this regard, too. The silence in the house, now, is so loud.

You are a gracious gentleman.

Thank you, again.

FrankM

Last edited by Moonson

 

Moonson posted:

MELGAR, THANK YOU for so informative a reply about bridge shoes. Your succinct explanation was a nice lesson to learn.

And more importantly, your very, very kind viewpoint of my layout work has given me the first big smile I have had in a couple weeks, now.

Thank you, also, for your thoughtfulness in asking about how I am getting along. Little by little, bit by bit. I am learning in this regard, too. The silence in the house, now, is so loud.

You are a gracious gentleman.

Thank you, again.

FrankM

The coefficient of thermal expansion for carbon steels is about six-millionths of an inch per linear inch per degree F.  Now some alloy steel gauge blocks I have used only had about three-millionths ratio.

 

Ron

Moonson posted:

MELGAR, THANK YOU for so informative a reply about bridge shoes. Your succinct explanation was a nice lesson to learn.

And more importantly, your very, very kind viewpoint of my layout work has given me the first big smile I have had in a couple weeks, now.

Thank you, also, for your thoughtfulness in asking about how I am getting along. Little by little, bit by bit. I am learning in this regard, too. The silence in the house, now, is so loud.

You are a gracious gentleman.

Thank you, again.

FrankM

FrankM,

The most important thing to me is that my comment gave you a little something to smile about.

MELGAR

 

PRRronbh posted:

The coefficient of thermal expansion for carbon steels is about six-millionths of an inch per linear inch per degree F.  Now some alloy steel gauge blocks I have used only had about three-millionths ratio.

Ron

I'm not quite sure of the purpose of your comment but if you are seeking engineering justification, I'll give you some numbers.

Length of bridge = 225 feet = 2700 inches

Temperature range (0 deg-F to 120 deg-F) = 120 deg-F

Expansion = (6E-6 inch/inch/deg-F) * 2700 inches * 120 deg-F = 1.944 inches

Strain = Expansion/Length = 1.944 inches / 2700 inches = 0.00072

Young's Modulus (carbon steel) = 29,000,000 psi

Stress = Young's Modulus * Strain = (29E6 psi) * 0.00072 = 20,880 psi

So, if the lower truss member of this example is mounted at 60 deg-F with no provision for expansion/contraction, the compressive stress at 120 deg-F would be 10,440 pounds-per-square-inch and the tensile stress at 0 deg-F would be 10,440 psi. Yield stress would be about 50,000 psi.

The other point is that bridge shoes of the type in our models allow the structure to rotate freely about the pin in the shoe, which produces zero bending-moment to be transmitted into the structure through the shoe.

MELGAR

 

Last edited by MELGAR

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OGR Publishing, Inc., 1310 Eastside Centre Ct, Ste 6, Mountain Home, AR 72653
800-980-OGRR (6477)
www.ogaugerr.com

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