Well lest see if I can do this without getting too involved...
First thing is that the voltage coming out of the transformer, any O scale transform will be a max of 18-22 VAC. That's the main job of the transformer, to change the 120 VAC mains voltage to a lower voltage suitable and safe to run the trains.
Next, at full power, a chopped wave and a pure wave transformer with the same max output will put (almost) the same amount of power on the track. The chopped wave type works by "chopping" part of the wave off of a pure wave. when the throttle is all the way up, nothing (almost) is chopped off. (The almost comes in, in that in typical designs a very small fraction of the wave will always be cut, perhaps .1 percent.)
Where the difference comes in is when the throttle is set to less than full. Here on a pure sine wave transformer, the peak to peak voltage of the wave changes. On a 'chopped wave' transformer, the peak to peak voltage remains at the 'full power' voltage at anything over 25% throttle. engines with electronics inside that convert the AC track power to DC will 'see' full throttle voltage with as little as 25% throttle. This is why modern smoke units function better on chopped wave type transformers, they get full power even when the throttle is set low.
While not exactly your question This Thread discusses how chopped wave transformers function in great detail.
To best answer your question, post war transformers generally are capable of supplying a bit more voltage than modern ones, usually about 20 volts, whereas modern ones are designed to supply only 18 VAC. For post war locomotives this may make a difference, but over all it really doesn't. The CW80 at max throttle (18VAC) will supply the same voltage as a postwar transformer set to 18VAC output.
On a modern locomotive for conventional running the CW80, or other chopped wave type transformer, will provide better performance than a pure wave transformer when set to less than full throttle, and will provide identical performance at full throttle.
JGL