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Need help re-wiring my Lionel #38 pumping water tower (1947 version). While I was cleaning and lubricating the motor that drives the water pump, the original wires to the motor broke and I cannot figure out how to reconnect them.  Where are the wires coming from each brush suppposed to terminate at their other end ?  I cannot find an on-line wiring diagram that specifies exactly where the other end of those two wires should terminate.

     

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I looked at my repair guide but it only shows the spout wiring. It does says that when you when you push the controller the spout comes down and the pump moves the water. One leg of the spout solenoid is grounded through the base plate and the other lead goes to the insulated post. For the pump to work it would have to be connected in the same way: one lead to the same ground and the other lead to the insulated post. Good luck.

Solved my wiring problem and pump now works like a charm. though 66 years old. The pumping tower contains two electrically-powered elements: a solenoid to let the spout drop, and a motor that drives the water pump. The motor has two brushes to energize the rotating magnets, and a wire to energize a static magnet. The solenoid and motor can be wired in series or in parallel. If wired in series, the tower requires 15+ volts to run solenoid plus motor simultaneously. If wired in parallel, a fixed 9 volts easily runs solenoid plus motor simultaneously. To wire in series: connect insulated terminal at tower base to one side of solenoid; connect other side of solenoid to one brush on motor. Connect motor's other brush to one end of the wire that energizes the motor's static magnet. Ground the other end of the wire that energizes that static magnet, by connecting it to the non-insulated terminal at metal tower base or to any metal that is connected to that metal tower base.

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