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I have a Premier Genset ps2 /3 volt  # 20-20002-1 .      I've replaced incandescent bulbs in series  with LEDs with a 220 ohm resistor per instructions from Gunrunner John in the past in this kind of scenario.

I only have one 220 in my drawer that I could use for the front double headlight but for the rear double LEDs I only have a half dozen 150 ohms and about fifty 460s.

Can I use two 150 s  inline to get to a value closer to the 220 single.    Do I have a certain arraingement of the 150s to work with the two LEDs in series ?

Thanks

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@MartyE posted:

Unless I'm mistaken, 2-460 ohm resistors in parallel would be closer at 230 ohms.

You know Marty , I  couldn't find the post on " search "  that described the situation about doubling resistors but I thought there was something odd about the math that didn't apply to conventional thinking . 

What would the two resistors in parallel with the two white LEDs in series look like ?

Thanks for the quick reply........I don't like opening these locomotives more than necessary. 

From my basic electrical engineering course, putting the resistance in series just adds them together.  

R = r1 + r2

Putting them in parallel, divides them : 

R = 1/r1 + 1/r2

So in series it should be 300 ohm resistance and in parallel 75 ohm resistance.    Someone mentioned about 2 460s in parallel should be about 230.  

the 300 is probably a good solution.    the LED may be a little dimmer, but may not notice.

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