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It's easy.  A mile per hour is 5280 feet/3600 second or 1.467 feet/second.

 

Your train went 44 feet/25 second or 1.76 feet/second.  If you divide this number by 1.467 you get 1.19 real miles per hour.  Since O scale is 1/48 of full scale, multiply 1.19 by 48 gives you 57.2 scale miles per hour (smph).

 

Another way to look at is to divide a mile (5280 feet) by 48 which gives you 110 feet.  That is the length of a scale mile.  so you went

 

    ((44 feet)/(110 ft/scale mile))

-------------------------------------------  =  57.6 smph

((25 seconds)/3600 seconds/hour))

 

Of course this leads into a discussion of a "fast clock".  We'll leave this for later.

 

Jan

Measure 11 feet on your track, time how many seconds it takes your train to travel the 11 feet, then use this chart:

 

SCALE SPEED TABLE
Time to TravelO Gauge
11 FeetSCALE
(in seconds)MPH
  
490.0
4.580.0
572.0
5.565.5
660.0
6.555.4
751.4
7.548.0
845.0
8.542.4
940.0
9.537.9
1036.0
1132.7
1230.0
1327.7
1425.7
1524.0
1622.5
1721.2
1820.0
1918.9
2018.0
2117.1
2216.4
2315.7
2415.0
2514.4
2613.8
2713.3
2812.9
2912.4
3012.0
3510.3
409.0
458.0
507.2
556.5
606.0

 

Sorry, I don't know how to make an Excel file reproduce better in this forum.

.....

Dennis

Last edited by Dennis

Most steam engines in  Canada  didn't  have speedometers  and the engineers would count the telegraph poles in say "10 seconds". They had a formula worked out to give the actual speed .   There are 40 telegraph  poles to the mile with mileage signs which start at the initial terminal for that subdivision... In CTC the signal numbers on the mask  are also the mileage numbers.

 

I can't remember the formula. 40 poles in 60  seconds would be equal to sixty miles per hour  anyone?

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