As a follow on to my post of yesterday, I'll describe an approximate method to construct a spiral. Then one only has to use geometry to determine what the offset is. Having the offset, one then needs only a method of using a spline in such a way that the length of spiral produced will match that offset. [I will describe a method for that tomorrow. BTW, a spline is the engineering office name for a small, flexible plastic strip. They come in a polished walnut case, with their 5 whales... like fine whiskey. ]
For an approximation to a spiral, we could use for example. a piece of 0-144 as a spiral for an 0-72 curve. This would be super easy in the calculations, as the spiral would begin and end with the 0-144 section, assuming both were 1/16 of a circle. This would be called a one-segment approximation. But there is a better approximation, which I devised, in a desperate effort to improve our draftsperson's speed and polish on the drawing with these spirals, when encountered.
This would be the two-segment approximation, my term. [In our office calculations, we used the three-segment approximation, which was said be truly marvelous in its closeness to the real thing. It had a tangent segment and two curved segments, identified by our IBM 650-- literally an electronic Frieden. The program was written by an insane professor-- we called it the research program.] So don't sneeze at a mere two-segment approximation, even with only one curve.
Let's say 0-72 is a curve of 40 degrees-- that is, it turns through an angle of 40 deg in a distance of 100 scale feet (about 25" in 1:48, along the arc of its center rail). Now let's take a curve of 0-54. Notice that 54/72 is 3/4. Or in degrees of curvature, 0-72 is 3/4 as sharp as an 0-54 central curve. Both track have 16 sections per circle. Suppose we ease a central curve of 0-54 using a section of 0-72. And further suppose we say that the 0-72 segment is 2/3 the length of the two-segment spiral we are creating. What do we then have?
Well, 4/3rds the original tinplate track-section length with 3/4ths the degree of original 0-54 curvature will give [4/3 x 3/4] the same total curvature. So we don't need more curvature, but we do need more spiral "approximation" length, which will be a segment of tangent (ie, straight) track. Suppose we make that tangent half as long as the piece of 0-72, which is the curved segment.
So then the total spiral becomes 4/3rds curved plus 2/3rds tangent, with a length of 6/3rds, or twice, the length of the original curved 0-54 track section replaced. That the spiral be twice the length of the amount of constant curvature central curve replaced is one of the conditions imposed upon spirals for railroad use. I will explain why in future post, perhaps after I explain the use of the spline (and its whales...) to substitute a smooth spiral "approximation" for the two-curve approximation [tomorrow].
But first, to conclude the issue of use of an approximate spiral to obtain approximate offsets, note that: The offset for 0-54 eased by a section of 0-72 is very close to 5/8". (I mean that working to 32nds, it would be 20/32nds or 5/8".) The length of the two-segment spiral approximation is the length of the 0-72 curve (14-3/8" IIRC) plus a tangent of half that (7-3/16"), total 21-9/16", which is 86'-6", and conveniently as long as a 21+ inch car.
Second, there is another pair of radii with readily available tinplate (or other prefab arrangements) in 0 scale: I refer to the 0-72" eased by an 0-96 section. These are sections available in 16 per circle also. Thus the various lengths will be proportionate; in particular the offset will be 5/6" (4/3 x 5/8 = 20/24ths = 5/6"). The triangular engineer's and architect's scales will be useful in laying centerlines to such dimensions-- available in stationery stores; in plastic fairly inexpensive.
The scale person will of course be interested in the 48" curve, if not also the 60 (0-96 and 0-120). Following the principles of the first two examples, suitable offsets can be worked out, on paper without need for sectional track. Nor need they need to be proportional to the examples. Railroads almost invariably used a 200-foot spiral (altho sharp curves could require more). Somewhere around a 100-foot spiral seems an acceptable compression in the model.
Just remember the rule is, for the two-segment approximation, for the curve segment: Use three-fourths the (degree of) curvature for two-thirds of the spiral length; tangent for the remaining one-third length. Calculate the offset at the two-thirds point.
I'm sure I don't have to explain how to figure the outward offset when only a single compound to a 2nd radius is involved, so this essentially concludes the determination of offset procedure. Smoothing with spline covered Wednesday.
--Frank